deliver full path by argv[0] and GetCommandLine for win9x
Juan Lang
juan_lang at yahoo.com
Thu Feb 12 12:22:56 CST 2004
--- Alexandre Julliard <julliard at winehq.com> wrote:
> No, the interesting case is what happens with
> CreateProcess. Launching
> the app from cmd.exe doesn't tell you anything,
> because you don't know
> exactly what arguments cmd.exe passed to
> CreateProcess.
You're right, as usual :)
I created another test case:
#include <windows.h>
#include <stdio.h>
int main(int argc, const char *argv[])
{
if (argc <= 1)
{
PROCESS_INFORMATION procInfo;
STARTUPINFO startInfo;
memset(&startInfo, 0, sizeof(startInfo));
startInfo.cb = sizeof(startInfo);
if (CreateProcessA(NULL, "cmdlinetest.exe 1",
NULL, NULL, FALSE,
0, NULL, NULL, &startInfo, &procInfo))
{
CloseHandle(procInfo.hProcess);
CloseHandle(procInfo.hThread);
}
}
else
{
LPCSTR cmd;
printf("argv[0] is %s\n", argv[0]);
cmd = GetCommandLineA();
printf("GetCommandLine returns %s\n", cmd);
}
return 0;
}
With this, the output under win9x is:
argv[0] is cmdlinetest.exe
GetCommandLine returns cmdlinetest.exe 1
So, Frank, sorry, this isn't the way GetCommandLine
actually behaves under Win9x.
--Juan
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