dlls/winmm/winealsa/midi.c: Bug in MIDI_CMD_BENDER fixed

[Johannes Koch]

No, you don't. The bitwise shifting operator has a higher precedence
than the bitwise or does.
You may test it with this programm:

#include <stdio.h>

int main(int agrc, char** argv)
{
   int iTest = 0x42 << 7 | 0x02;
   int iTest1 = (0x42 << 7) | 0x02;
   int iTest2 = 0x42 << (7 | 0x02);

   printf("iTest: %d; iTest1: %d, iTest2: %d\n", iTest, iTest1, iTest2);

   return 0;
}

I get the following output(compiled with gcc 3.3.5):
iTest: 8450; iTest1: 8450, iTest2: 8448

Greetings,
Johannes